Data Sufficiency Answer Set-1

Data Sufficiency Answer Set-1

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1. From st. a x is prime factor of 42
42 can be written as 6.7, 21.2, 14.3, and 42.1
In the above list (6,7), (21,2) and (14,3) are co-primes
From st. b the range of x is given 5 £ x £ 11
Prime no. in this range is 7
Hence the value of x using both statements is 7.

2. From st. a 7 4x – 1 = 343
7 4x – 1 = 73
4x – 1 = 3
4x = 4
x = 1
From st. b 7 x+y = 49 4
7 x+y = 7 8
x + y = 8
using value of x = 1 in then y = 8 – 1 = 7
the value of y – x = 7 – 1 = 6.
Using both sts. We can get the answer.

3. St. a is not required in this case as square of any no. is positive
hence we will consider st. b given x3 < 0 which implies x < 0
here we could answer the question.
st. b is enough to answer.

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4. St. a AC = 40

St. b AB = BC
AC2 = AB2 + BC2
2AB2 = 402
AB2 = 800
AB = 20Ö2
Area can be calculated.
Hence both the sts are required


5. st. a
B = 1
G + 10
B = G + 10
st. b
B + 20 = 3
G 1
Using both G + 10 + 20 = 3G
2G = 30
G = 15
B = 15 + 10
Hence both the sts are required.


6. st. a area = 289p

pr2 = 289p
r = 17
st. b
r + w = 23
using both sts
17 + w = 23
w= 6


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7. st. a A = C + 4
st. b 3A + 5C = 92
using both sts
3( C + 4 ) + 5C = 92
8 C = 80
C = 10
A = 14
Amount of 40 Adults and 50 Children can be calculated
Hence both the sts are required.



8. The question gives x + y + z = 45
st. a no.s are positive
st. b all the no.s are consecutive odd no.s
Using both the sts. By trial and error x, y, and z are 13, 15, and 17
Hence both sts. are required



9. st. a total balls are 36
st. b ratio of red and black is given as 2 : 1
No information of green balls is given.
Hence neither of the sts. are sufficient.


10. st. a 9x – 5y = 21
st. b 3x – 5y = 7
3
9x – 5y = 21
only one equation is given
hence neither of the sts. are sufficient.


11. st. a the wt of the packet is given as 800gms
st. b the cost of 500gms is Rs.75 and each additional 50gms costs
Rs.5 using both the sts. cost of the packet = 75 + 6.5 = 105
hence both the sts. are sufficient

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12. st. a gives the ratio of a : b : c = 4 : 5 : 6
st. b gives the semi perimeter (a + b + c) /2= 22.5


We can find out the area. Hence using both the sts. we can get the area.

Note: In data sufficiency there is no need to get exact answer. We should see whether we can get the answer using data given in both the sts.

13. st. a gives the sides of the triangle 17, 15, and 12
st. b gives the perimeter of the triangle as 44
to get the ratio a check should be done, when sides in st. a are
added can be the perimeter given in st. b
17 + 15 + 12 = 44
using area of triangle = s.r
and s = ( a + b + c )/2
we can find the ratio of semi perimeter and the in radius.
Hence both the sts. are required

14. st. a Vc = Vs 2
st. b radius of sphere is 9
using both the sts.
volume of sphere can be calculated and we can calculate the volume of cylinder.
Hence both the sts. are required.

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15. st. a C finished second
st. b D,E, and F are disqualified
but no data about A and B is not given.
Hence neither of the sts. are sufficient.


16. st. a W consumes more carbohydrates
st. b X and Y consume more proteins
who is heaviest can’t be determined.
Hence neither of the sts. are sufficient.



17. st. a Christmas is celebrated on 25th Dec
st. b day after tomorrow is 26th Dec
using both sts. we can answer the question
Hence both the sts. are sufficient.

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18. st. a the height of the wall is given

st. b the angle made by the ladder and the floor is given
using both the sts. we can be

using sin q = opposite /hypotenuse will give the length of the ladder. Hence both the sts. are sufficient.



19. st. a Area of rectangle = 180
st. b change of length, breath and corresponding perimeter of rectangle is given.
Using both the sts. % change in area can be calculated.
Hence both the sts. are required.


20. st. a 3cm snowfall for first fifteen days in January

st. b 4cm snowfall for the following fifteen days in January
using both sts. the information is for 30days ,where as January has 31 days
we can’t determine the average snowfall.
Hence neither of the sts. are sufficient.

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